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-4x^2-5x+5=0
a = -4; b = -5; c = +5;
Δ = b2-4ac
Δ = -52-4·(-4)·5
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{105}}{2*-4}=\frac{5-\sqrt{105}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{105}}{2*-4}=\frac{5+\sqrt{105}}{-8} $
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